`0.5x-(0.8-0.2x)=0.2-0.3x`

Determine which of the following can be probability distributions of a random variable X: (i) X: 0 1 2 (ii) X: 0 1 2 P(X): 0.4 0.4 0.2 P(X): 0.6 0.1 0.2 (iii) X: 0 1 2 3 4 P(X): 0.1 0.5 0.2 -0.1 0.3

[0.2x+0.3y=1.3],[0.4x+0.5y=2.3]

{:(0.4x + 0.3y = 1.7),(0.7x - 0.2y = 0.8):}

Q. If 1.5 0 (b) (2x-3)(2x-9) =0 (d) (2x-3)(2x-9)<=0

{:(0.04x + 0.02y = 5),(0.5(x - 2) - 0.4y = 29):}

Solve, using cross - multiplication : 0.4x + 1.5y = 6.5 0.3x + 0.2y = 0.9

A random varibale X has the following probability distribution. {:(X:,1,2,3,4,5),(P(X):,0,0.1,0.2,0.3,0.4):} Find the mean.

if 9^(x+2)=240+9^x , then x= (a) 0. 5 (b) 0.2 (c) 0.4 (d) 0.1

Solve: 2.3x-0.4=2.8+0.7x

A quadratic equation whose roots are cosec^2theta and sec^2theta can be (1) x^2-2x+ 2 =0 (2) x^2-3x + 3 = 0 (3) x^2-3x+ 4= 0 (4) x^2-5x+5= 0