`( 3/4)^5` . `( 1/3)^6`

The sum of the infite series (1/3)^(2)+1/3(1/3)^(4)+1/5(1/3)^(6) +……..is

The sum of the series 1+ 2/3+ (1)/(3 ^(2)) + (2 )/(3 ^(3)) + (1)/(3 ^(4)) + (2)/(3 ^(5)) + (1)/(3 ^(6))+ (2)/(3 ^(7))+ …… upto infinite terms is equal to :

Solve (a) 2/3 + 1/7 (b) 3/10 + 7/15 (c) 4/9 + 2/7 (d) 5/7 + 1/3 (e) 2/5 + 1/6 (f) 4/5 + 2/3 (g) (3/4) (1/3) (h) (5/6) (1/3) (1) 2/3 + 3/4 + 1/2 (1) 1/2 + 1/3 = 1/6 (k) (1) 1/3 + (3) 2/3 (1) (4) 2/3 +(3) 1/4 (m) ((16)/5))(7/5)

Evaluate : a. 6^(3)-:6^(3) b. 5^(4)-:5^(4) c. (-3)^(5)-:(-3)^(5) d. ((3)/(5))^(4)-:((3)/(5))^(4)

Evaluate: c. 5 (1)/(4) xx 3 (5)/(6) + 1 (3)/(5) div 5 (1)/(3)

Find the sum of the following series: 1/2+1/(3^2)+1/(2^3)+1/(3^4)+1/(2^5)+1/(3^6)+...+oo

Sum the following geometric series to infinity: (sqrt(2)+1)+1+(sqrt(2)-1)+oo 1/2+1/(3^3)+1/(2^3)+1/(3^4)+1/(2^5)+1/(3^6)+oo

Multiply and express as a mixed fraction : (a) 3 xx 5 1/5 (b) 5 xx 6 3/4 (c) 7 xx 2 1/4 (d) 4 xx 6 1/3 (e) 3 1/4 xx 6 (f) 3 2/3 xx 8

Show that 1 + 1/2.(3/5) + (1.3)/(2.4) (3/5)^2 + (1.3.5)/(2.4.6) (3/5)^3 + …… = sqrt([5/2])

Evaluate : a. (-1)^(11) b. (-3)^(2)xx(5)^(3) c. 6^(2)xx3^(3) d. (-2)^(3)xx(-5)^(2) e. (-1)^(7)xx2 f. (-1)^(4)xx(-1)^(5) g. 4^(3)xx3^(4) h. (-2)^(5)xx5^(3) i. (-4)^(3)xx(-6)^(3) j. (-1)^(33)xx(-3)^(1) k. ((-1)/(6))^(2) l. ((2)/(11))^(3)