`(- 3/5)^-4` . `( - 2/5)^2`

If the surm of the first ten terms of the series, (1 3/5)^2+(2 2/5)^2+(3 1/5)^2+4^2+(4 4/5)^2+........ , is 16/5m ,then m is equal to

If the sum of the first ten terms of the series (1 3/5)^2+(2 2/5)^2+(3 1/5)^2+4^2+(4 4/5)^2+. . . . . , is (16)/5 m, then m is equal to: (1) 102 (2) 101 (3) 100 (4) 99

Name the octants in which the following points lie: (1, 2, 3) , (4, -2, 3) , (4, -2, -5) , (4, 2, -5) , ( -4, 2,-5) , ( -4, 2, 5) , (-3, -1, 6) , (2, -4, -7) .

Simplify: (i) (3/4)^2 (ii) ((-2)/3)^4 (iii) ((-4)/5)^5

Show that 1 + 1/2.(3/5) + (1.3)/(2.4) (3/5)^2 + (1.3.5)/(2.4.6) (3/5)^3 + …… = sqrt([5/2])

Simplify : (i) (5/8)^(-7)×\ (8/5)^(-5) (ii) ((-2)/3)^(-2)×\ (4/5)^(-3)

The image of the point (1, 3, 4) in the plane 2x-y+z+3=0 is (3,\ 5,\ 2) b. (-3,5,\ 2) c. (3,\ 5,\ -2) d. (3,\ -5,\ 2)

Simplify: (i)   (-3)^2xx((-5)/(12))^2 (ii) ((-2)/5)^3-:((-3)/(10))^4

Simplify the following : (2""4/5-1""3/5) div (3""3/5-2""1/5) .

The sum of the infinite series, 1 ^(2) -(2^(2))/(5) + (3 ^(2))/(5 ^(2))+ (4^(2))/(5 ^(3))+ (5 ^(2))/(5 ^(4))-(6 ^(2))/(5 ^(5)) + ..... is: