`(sintheta-costheta)^2=1-2sintheta.costheta`

If 3cottheta=2 , find the value of (4sintheta-3costheta)/(2sintheta+6costheta)

(i) If tantheta=(a)/(b) ,then find the value of (2sintheta-3costheta)/(2sintheta+3costheta)

Prove: ((1+sintheta-costheta)/(1+sintheta+costheta))^2=(1-costheta)/(1+costheta)

Prove that: (1+sintheta-costheta)/(1+sintheta+costheta)=tan(theta/2)

Prove that: (1+sintheta-costheta)/(1+sintheta+costheta)=tantheta/2

3(sintheta-costheta)^(4)+6(sintheta+costheta)^(2)+4(sin^(6)theta+cos^(6)theta)=?

Prove that : (sintheta-costheta)/(sintheta+costheta)+(sintheta+costheta)/(sintheta-costheta)=(2)/(2sin^(2)theta-1)

Prove that: (sintheta-costheta+1)/(sintheta+costheta-1)=1/(sectheta-tantheta)

If 4 tantheta=3, then ((4sintheta-costheta)/(4 sintheta+costheta)) is equal to

Prove that (sintheta-costheta+1)/(sintheta+costheta-1)=1/(sectheta-tantheta) , using the identity sec^2theta=1+tan^2theta