`(sin^4theta+cos^4theta)/(1-2sin^2thetacos^2theta)=1`

Prove the following identities: sin^8theta-cos^8theta=(sin^2theta-cos^2theta)(1-2sin^2thetacos^2theta)

Prove the following identities: 2(sin^6theta+cos^6theta)-3(sin^4theta+cos^4theta)+1=0 sin^6theta+cos^6theta+3sin^2thetacos^2theta=1 (sin^8theta-cos^8theta)=(sin^2theta-cos^2theta)(1-2s in^2thetacos^2theta)

Prove the following identity: (1/(sec^2theta-cos^2theta)+1/(cos e c^2theta-sin^2theta))sin^2thetacos^2theta=(1-sin^2thetacos^2theta)/(2+sin^2thetacos^2theta)

Prove the following identity: (1/(sec^2theta-cos^2theta)+1/(cos e c^2theta-sin^2theta))sin^2thetacos^2theta=(1-sin^2thetacos^2theta)/(2+sin^2thetacos^2theta)

(1+sin2theta+cos2theta)/(1+sin2theta-cos2theta)=?

Prove that sin^6theta+cos^6theta=1-3sin^2thetacos^2theta

The value for 2(sin^6theta+cos^6theta)-3(sin^4theta+cos^4theta) +1 is

Prove : (1+sin2theta-cos2theta)/(1+sin2theta+cos2theta)=tantheta

Prove that: a) (sin2theta)/(1+cos2theta) = tantheta b) (1+sin2theta+cos2theta)/(1+sin2theta-cos2theta)=cottheta

Prove that: (1+sin2theta+cos2theta)/(1+sin2theta-cos2theta)=cot theta