(i) `1/(3+sqrt7)+1/(sqrt7+sqrt5)+1/(sqrt5+sqrt3)+1/(sqrt3+1)=1`

1/(sqrt5 +sqrt3 +2) + 1/(-sqrt5 +sqrt3 +2 ) =

The value of { 1/(sqrt6 - sqrt5) - 1/(sqrt5 - sqrt4) + 1/(sqrt4 - sqrt3) - 1/(sqrt3 - sqrt2) + 1/(sqrt2 - 1)} is :

Prove that (i) (1)/(3+sqrt(7)) + (1)/(sqrt(7)+sqrt(5))+(1)/(sqrt(5)+sqrt(3)) +(1)/(sqrt(3)+1)=1 (ii) (1)/(1+sqrt(2))+(1)/(sqrt(2)+sqrt(3))+(1)/(sqrt(3)+sqrt(4))+(1)/(sqrt(4)+sqrt(5))+(1)/(sqrt(5)+sqrt(6))+(1)/(sqrt(6)+sqrt(7)) +(1)/(sqrt(7)+sqrt(8))+(1)/(sqrt(8) + sqrt(9)) = 2

1/(sqrt(2)+sqrt(3)+sqrt(5))+1/(sqrt(2)+sqrt(3)-sqrt(5))

Show that: 1/((3-sqrt8))-1/((sqrt8-sqrt7))+1/((sqrt7-sqrt6))-1/((sqrt6-sqrt5))+1/((sqrt5-2))=5