`sqrt(6+sqrt(6+sqrt(6+.........)=?`

(6 + sqrt6)(6 - sqrt6)

(6+sqrt(6))(6-sqrt(6))

If tan theta=sqrt(6+sqrt(6+sqrt6+...)) then sec^2 theta=

Evaluate : ( sqrt(3) - sqrt(6) ) / ( sqrt(3) + sqrt(6))

Evaluate : ( sqrt(3) - sqrt(6) ) / ( sqrt(3) + sqrt(6))

Evaluate : ( sqrt(3) - sqrt(6) ) / ( sqrt(3) + sqrt(6))

(3-sqrt(6))/(3+2sqrt(6))=a sqrt(6)-b

Find the angle between the plane x+y-2z+5=0 and the line whose direction cosines are 1/sqrt(6),2/sqrt(6),1/sqrt(6) .

Evaluate ( sqrt(24) + sqrt(6) )/( sqrt(24) - sqrt(6))