A body of mass "1kg" is moving according to the law `x(t) =(5t+4t^(2)+6t^(3))m`.The force acting on the body at time t = 2s is

A boat of mass 300 kg moves according to the equation x= 1.2t^(2) - 0.2 t^(3) . When the force will become zero ?

A body of mass 2kg travels according to the law x(t) = pt + qt^(2) + rt^(3) where , q = 4 ms^(-1) , p = 3 ms^(-1) and r = 5 ms^(-1) . The force acting on the body at t = 2s is

A body of mass 2kg travels according to the law x(t) = pt + qt^(2) + rt^(3) where , q = 4 ms^(-2) , p = 3 ms^(-1) and r = 5 ms^(-3) . The force acting on the body at t = 2s is

A body of mass 2kg travels according to the law x (t) = pt + qt^(2) + rt^(3) where p = 3ms^(-1),q = 4 ms^(-2) and r = 5ms^(-3) . Find the force acting on the body at t=2 sec.

The position of a body moving along x-axis at time t is given by x= (t^(2)-4t+6)m . The velocity of the body at time t = 3s is

The displacement of a particle of mass 2kg moving in a straight line varies with times as x = (2t^(3)+2)m . Impulse of the force acting on the particle over a time interval between t = 0 and t = 1 s is

If a particle moves according to the law s=6t^(2)-(t^(3))/(2) , then the time at which it is momentarily at rest is

The momentum of a body in two perpendicular direction at any time 't' are given by P_(x) =2t^(2) + 6 and P_(y) = (3t^(2))/2 + 3 . The force acting on the body at t= 2 sec is

The momentum P ( in kg ms^(-1) ) of a particle is varying with time t ( in second ) as p=2+ 3t^(2) . The force acting on the particle at t=3s will be

The momentum p (in kg ms^(-1) ) of a particle is varying with time t (in second) as p=2+3 t^(2) . The force acting on the particle at t=3s will be