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If (b+c-a)x=(c+a-b)y=(a+b-c)z=a+b+c, the...

If `(b+c-a)x=(c+a-b)y=(a+b-c)z=a+b+c`, then `1/x+1/y+1/z=?`

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If a^x = b^y = c^z and b/a = c/b then (2z)/(x + z) is equal to: