`frac{sqrt 7 - sqrt 5 }{sqrt 7 + sqrt 5 }`

2sqrt5 - sqrt5 = sqrt5

Simplify: (sqrt 3 - sqrt 5)(sqrt 5+ sqrt 3)

If sqrt (7 sqrt (7 sqrt7 sqrt7 sqrt7)) = 7 ^(x) then find the value of x

Simplify {(\sqrt 5+\sqrt 3)\times (\sqrt 5 - \sqrt 3)}/(\sqrt 7- \sqrt 3)\times (\sqrt 7+ \sqrt 3)/(\sqrt 7+\sqrt 3)

Simplify : (\sqrt 5 - \sqrt 3)/(\sqrt 3 + \sqrt 5) \times (\sqrt 5 - \sqrt 3)/(\sqrt 3 -\sqrt 5)

frac{1}{sqrt7-4} frac{1}{sqrt11-7}

{:(sqrt(5)x - sqrt(7)y = 0),(sqrt(7)x - sqrt(3)y = 0):}

If (3 + sqrt7)/(3 - sqrt7) = a + bsqrt7 , then ( a , b ) =

Find the number of terms in the following expansions. ( sqrt(3) + sqrt(5) )^(7) ( sqrt(3) - sqrt(5) )^(7)

Simplify: (\sqrt 5+\sqrt 3)/(\sqrt 5 - \sqrt 3)\times (\sqrt 5+\sqrt 3)/(\sqrt 5 +\sqrt 3)