`frac{2+sqrt 2}{sqrt 2}`

solve the equations: frac{2}{sqrt x} + frac{3}{sqrt y} =2 and frac{4}{sqrt x} - frac{9}{sqrt y} =-1

Find (sqrt3 - sqrt 2)/(sqrt 3+sqrt 2) -(sqrt3 + sqrt 2)/(sqrt 3-sqrt 2) +1/(sqrt2+1)-1/(sqrt2-1)

frac{1}{sqrt7-4} frac{1}{sqrt11-7}

sqrt 2(sqrt 2+1) - sqrt 2 (1+sqrt2) =?

The value of "log"_(sqrt(2)) sqrt(2sqrt(2sqrt(2sqrt(2)))) , is

Rationalize the denominator: (2 + sqrt 3)/(2 - sqrt 3) + (2 - sqrt 3)/(2 + sqrt 3) + (sqrt 3 - 1)/(sqrt 3 + 1)

1/(sqrt3 + sqrt2) + 1/(sqrt3 -sqrt2)=

Rationalize the denominator 1/(sqrt 3 - sqrt 2) - 2/(sqrt 5 - sqrt 3) + 3/(sqrt 5 - sqrt 2)

Simplify: (sqrt3/2)^2 -(sqrt3)^2+(sqrt 2)^2 +1/2

If x=(sqrt2+1)/(sqrt2-1) ,then x+frac1x=?