`y(dy)/(dx)=2x-y^(2)`

Solution of 2y sin x(dy)/(dx)=sin2x-y^(2)cos x,x=(pi)/(2),y=1 is given by

If y(dy)/(dx) = x[(y^(2))/(x^(2)) +(phi((y^(2))/(x^(2))))/(phi'((y^(2))/(x^(2))))], x ge 0, phi gt 0 , y(1) = -1, then phi((y^(2))/(4)) is equal to :

The solution of differential equation 2y sin x(dy)/(dx)=sin2x-y^(2)cos x ,satisfying y((pi)/(2))=1 is

The first integral of (dy)/(dx)((d^(2)y)/(dx^(2)))-x^(2)y((dy)/(dx))=xy^(2) will be

x(dy)/(dx)-y=2x^(2)y

x+y(dy)/(dx) =x^(2) +y^(2)

y(dy)/(dx)=xe^(x^(2)+y^(2))

x+y(dy)/(dx)=sec(x^(2)+y^(2)), where x^(2)+y^(2)=u

Solve the following differential equation y x(dy)/(dx) = x^(2) + 2y^(2)

Solution of the differential equation x+y(dy)/(dx)=sec(x^(2)+y^(2)) is