If `A=`[[0,1],[1,0]]`,then the value of `A^2`

If A=[[0,1],[1,0]] , then A^2 is equal to: (a) [[0,1],[1,0]] (b) [[1,0],[0,1]] (c) [[1,0],[1,0]] (d) [[0,0],[1,1]]

If x in [-1,0], then find the value of cos^(-1)(2x^2-1)-2sin^(-1)x

Let A=[[2,2],[9,4]] and I=[[1,0],[0,1]] then value of 10 A^(-1) is-

If A=[[alpha,0],[ 1, 1]] and B=[[1, 0],[ 5, 1]], find the values of alpha for which A^2=Bdot

If A=[(2x,0),(x,x)] and A^(-1)=[(1,0),(-1,2)] , then the value of x is

Given A=[(4,2,5),(2,0,3),(-1,1,0)] write the value of det. ("2AA"^(-1)) .

If (A -2I)(A-3I)=0 , when A=[{:(4,2),(-1,x):}] and I=[{:(1,0),(0,1):}] , find the value of x