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If (3/5)^3(3/5)^-6=(3/5)^(2x-1)...

If `(3/5)^3(3/5)^-6=(3/5)^(2x-1)`

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If log_(e )k=2[(3)/(5)+(1)/(3)((3)/(5))^(3)+(1)/(5)((3)/(5))^(5)+….oo] then k =

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Evaluate : a. (-1)^(11) b. (-3)^(2)xx(5)^(3) c. 6^(2)xx3^(3) d. (-2)^(3)xx(-5)^(2) e. (-1)^(7)xx2 f. (-1)^(4)xx(-1)^(5) g. 4^(3)xx3^(4) h. (-2)^(5)xx5^(3) i. (-4)^(3)xx(-6)^(3) j. (-1)^(33)xx(-3)^(1) k. ((-1)/(6))^(2) l. ((2)/(11))^(3)