Simplify: `(1)/(sec theta+tan theta)`

Prove the following identities: (1)/(sec theta-tan theta)=sec theta+tan theta

Simplify sec theta[[tan theta,sec theta],[sec theta,-tan theta]] - tan theta[[sec theta,tan theta],[tan theta,-sec theta]]

Prove that (1)/(sec theta - tan theta) = sec theta + tan theta

Prove that (1)/((sec theta - tan theta))-(1)/(cos theta)=(1)/(cos theta)-(1)/((sec theta+ tan theta)).

Prove that: 1/(sec theta - tan theta) = sec theta + tan theta .

Prove that (i) (1)/(("cosec" theta- cot theta ))=("cosec" theta + cot theta) (ii) ((sec theta - tan theta))/((sec theta + tan theta))=(1+ 2tan^(2) theta - 2 sec theta tan theta)

Prove that quad (sin theta-cos theta+1)/(sin theta+cos theta-1)=(1)/(sec theta-tan theta) ,using the identity sec^(2)theta=1+tan^(2)theta

Prove that : (tan theta)/(sec theta + 1) = (sec theta - 1)/(tan theta)

prove that (sec theta-tan theta-1)/(sec theta+tan theta-1)=tan theta-sec theta

Prove that : (tan theta)/(sec theta -1) + (tan theta)/(sec theta + 1) = 2 cosec theta