pH of 0.01 M `Ca(OH)_2` solution is
1.7
2
10
12.3

The pH of 0.001 M Ba(OH)_(2) solution will be

The pH of M/(100) Ca(OH)_2 is

The pH of 10^(-2) M Ca(OH)_(2) is

What volume of 0.05 M Ca(OH)_(2) solution is needed for complete conversion of 10mL of 0.1 M H_(3)PO_(4) into Ca(H_(2)PO_(4))_(2) ?

Calculate pH for - 0.01 M Ca(OH)_(2)

pH of Ca(OH)_(2) solution is 12. Millimoles of Ca(OH)_(2) present in 100mL of solution will be