If `[[2,x+2],[y,-4]] = [[2,0],[-1,-4]]` then (x,y) is

Given A=[[1,-1, 0], [2, 3, 4], [0, 1, 2]], B= [[2,2,-4],[-4,2,-4],[2,-1,5]] find AB and use this to solve the system of equations: y+2x=7,x-y=3,2x+3y+4z=17

The equation of the circle passing through the point of intersection of the circles x^2+y^2-4x-2y=8 and x^2+y^2-2x-4y=8 and the point (-1,4) is (a) x^2+y^2+4x+4y-8=0 (b) x^2+y^2-3x+4y+8=0 (c) x^2+y^2+x+y=0 (d) x^2+y^2-3x-3y-8=0

The equation of the circle passing through the point of intersection of the circles x^2+y^2-4x-2y=8 and x^2+y^2-2x-4y=8 and the point (-1,4) is x^2+y^2+4x+4y-8=0 x^2+y^2-3x+4y+8=0 x^2+y^2+x+y=0 x^2+y^2-3x-3y-8=0

The equation of the circle passing through the point of intersection of the circles x^2+y^2-4x-2y=8 and x^2+y^2-2x-4y=8 and the point (-1,4) is x^2+y^2+4x+4y-8=0 x^2+y^2-3x+4y+8=0 x^2+y^2+x+y=0 x^2+y^2-3x-3y-8=0

Find x and y if [{:(,3,-2),(,-1,4):}] [{:(,2x),(,1):}] +2 [{:(,-4),(,5):}] =4[{:(,2),(,y):}]

Prove the identities: |[z, x, y],[ z^2,x^2,y^2],[z^4,x^4,y^4]|=|[x, y, z],[ x^2,y^2,z^2],[x^4,y^4,z^4]|=|[x^2,y^2,z^2],[x^4,y^4,z^4],[x, y, z]| =x y z (x-y)(y-z)(z-x)(x+y+z)

Find X if Y=[3, 2, 1 ,4] and 2X+Y=[1, 0, -3, 2] .

The circle passing through (1,1) and cutting the two circles x^2+y^2-4x-2y-4=0, x^2+y^2-2x-4y-4=0 othogonally is

Find x ,\ y satisfying the matrix equations: [x-y 2 -2 4x6]+[3-2 2 1 0-1]=[6 0 0 5 2x+y5] (ii) [x y+2z-3]+[y4 5]=[4 9 12]

The equation of the circle which cuts the three circles x^2+y^2-4x-6y+4=0, x^2+y^2-2x-8y+4=0, x^2+y^2-6x-6y+4=0 orthogonally is