`(1+tan^2A) cosA.SinA`=

The value of [(secA+tanA)(1-sinA)] is equal to (a) tan^2A(b)sin^2A (c) cosA (d) sinA

Prove that: sinA(1+tanA)+cosA(1+cotA)= secA+"cosec"A

Evaluate sin2A, cos2A and tan2A if: i) sinA=5/13 , ii) cosA=8/17 , iii) tanA=4/3

cosA/(1−sinA) =

Prove that: i) tan(45^(@)-A/2) = (1-sinA)/(cosA) ii) tan(45^(@)+A/2)= (cosA)/(1-sinA)

If (2sinA)/(1+sinA+cosA)=k then (1+sinA-cosA)/(1+sinA)=

Prove the following identities: (cosA)/(1-tanA)+(sin^2A)/(sinA-cosA)=sinA+cosA

If (tan^(3)A)/(1+tan^(2)A)+(cot^(3)A)/(1+cot^(2)A)=p secA"cosec"A+q sinA cosA , then :

In a right - angled triangle , it is given that A is an acute angle and tan A=5/12 (cosA+sinA)/(cosA-sinA)

If A is an obtause angle, then (sin^(3)A-cos^(3)A)/(sinA-cosA)+(sinA)/(sqrt(1+tan^(2)A))-2tanA cotA. is always equal to