`tan^-1((1-cosx)/sinx)`

Prove that tan^-1((cosx)/(1+sinx))=pi/4-x/2,\ x in (-pi/2,pi/2)

Differentiate tan^(-1)((cosx)/(1+sinx)) with respect to sec^(-1)xdot

Express tan^(-1)((cosx)/(1-sinx)) , -(pi)/2ltxlt(pi)/2 in the simplest form.

d/(dx){tan^(-1)((cosx)/(1+sinx))}e q u a l 1/2 (b) x (c) (1-x^2)/(1+x^2) (d) 1

d/dx((1-cosx)/sinx)=

d/dx((1-cosx)/sinx)=

Express each of the following in the simplest form: tan^(-1){(cosx)/(1-sinx)} ,where -pi/2 < x < pi/2 (ii) tan^(-1)((cosx-sinx)/(cosx+sinx)) , -pi/4 < x < pi/4

Differentiate the following functions with respect to x : tan^(-1){(cosx)/(1+sinx)},0ltxltpi

Differentiate the following functions with respect to x : tan^(-1){(cosx)/(1+sinx)} , 0 < x < pi

Differentiate tan^(-1){(cosx)/(1+sinx)},\ 0 le x le pi