Evaluate `int(x)/(sqrt((x+1)(x-2)))dx`

Evaluate: int(1)/(sqrt((x-1)(x-2)))dx

Evaluate; int(x)/(1+sqrt(x))dx

Evaluate :int(dx)/(sqrt((x-1)(2-x))) by the substitution x=1+sin^(2)theta .Hence,find the value of int_(1)^(2)(dx)/(sqrt((x-1)(2-x)))

Evaluate: int(x)/(x-sqrt(x^(2)-1))dx

Evaluate: int(x-1)/(sqrt(x^(2)-x))dx

Evaluate: int(x-1)/(sqrt(x^(2)-x))dx

Evaluate: int(x-1)/(sqrt(x^(2)-x))dx

Evaluate int(1+x)sqrt(x)dx

Evaluate: int(1)/(sqrt(x)+x)dx

Evaluate: (i) int1/(sqrt((x-1)(x-2)))\ dx (ii) int1/(sqrt(9+8x-x^2))\ dx