`inte^((x^2+1)/x)(1-1/x^2)dx=?`

inte^x((x^2+1)/(x+1)^2)dx=

int((x+1)dx)/(1-2x-x^(2))

int((1+x)^(2))/(x(1+x^(2)))dx=

Evaluate : (i) inte^(x)((1)/(x)-(1)/(x^(2)))dx (ii) inte^(x)((1)/(x^(2))-(2)/(x^(3)))dx (iii) inte^(x){sin^(-1)x+(1)/(sqrt(1-x^(2)))}dx (iv) inte^(x)(tanx+logsecx)dx

int(x^(2)-1)/(1-x)dx

int(x^(2)+1)/(x^(4)-x^(2)+1)dx= . . .

int (2x^2+1)/((x+1)(x-2)) dx

int(3x^(2)+1)/(x(x^(2)+1))dx

inte^x. (x^2+1)/(x+1)^2dx

int(x+1)/x^(1/2)dx=