If  `|[2,0,0], [4,3,0], [4,6,x]| = 42` then find `x`

If |[2x,-1],[4,2]|=|[3,0],[2,1]| then "x" is

If [(2x+y,3y),(0, 4)]=[(6, 0),( 6, 4)] , then find x .

If |[1, x, x^2], [x, x^2, 1], [x^2, 1, x]|=3, then find the value of |[x^3-1, 0, x-x^4], [0, x-x^4, x^3-1], [x-x^4, x^3-1, 0]|

If |[x,3, 6],[ 3, 6,x],[6,x,3]|=|[2,x,7],[x,7, 2],[ 7, 2,x]|=|[4, 5,x],[5,x,4],[x,4, 5]|=0, then x is equal to a. 0 b. -9 c. 3 d. none of these

If [x\ \ 4\ \ 1][[2, 1 ,2],[ 1, 0 ,2],[ 0 ,2,-4]][[x],[4],[-1]]=0 , find xdot

"If A"=[{:(,8,0),(,4,-2),(,3,6):}] and B=[{:(,2,-2),(,4,2),(,-5,1):}] then find the matrix X, such that 2A+3X=5B

If A=|(2,2,-4),(-4,2,-4),(2,-1,5)| and B=|(1,-1,0),(2,3,4),(0,1,2)| then find BA and use ths to sovle the system of equations y+2z=7, x-y=3 and 2x+3y+4z=17 .

Show that A=|[2,-3], [3 ,4]| satisfies the equation x^2-6x+17=0 . Hence, find A^(-1) .

Given A=[[1,-1, 0], [2, 3, 4], [0, 1, 2]], B= [[2,2,-4],[-4,2,-4],[2,-1,5]] find AB and use this to solve the system of equations: y+2x=7,x-y=3,2x+3y+4z=17

if 2A -3B =[{:(4,2),(-1,0),(3,-2):}]and 3A+B=[{:(1,0),(3,5),(-1,4):}] , then find the matrices A And B,