The value of `Gamma(6)` is

The value of gamma of linear, arragement of triatomic gas molecules is

The value of gamma=C_(P)/C_(V) for a gas is given by gamma=1+2/f where f is the number of degrees of freedom of a molecule of a gas What is the ratio of (gamma_("monoatomic"))/(gamma_("diatomic")) ?

Calculate the value of gamma for a gaseous mixture consisting n_(1) moles of oxygen and n_(2) moles of carbon dioxide. The values of gamma for oxygen and carbon dioxide are gamma_(1) and gamma_(2) respectively. Assume the gases to be ideal.

Calculate the value of gamma for a gaseous mixture consisting of n_(1) moles of oxygen and n_(2) moles of carbon of carbon dioxide. The values of gamma for oxygen and carbon dioxide are gamma_(1) and gamma_(2) respectively. Assume the gases to be ideal. [Hint: U_(m) = U_(1) + U_(2) and U = (nRT)/(gamma-1) ]

3 moles of a mono-atomic gas (gamma=5//3) is mixed with 1 mole of a diatomic gas (gamma=7//3) . The value of gamma for the mixture will be

If one mole of a monatomic gas (gamma=5/3) is mixed with one mole of a diatomic gas (gamma=7/5), the value of gamma for mixture is

One mole of monatomic gas [gamma =5/3] is mixed with two moles of polyatomic gas [gamma =4/3] The value of gamma for the mixture will be ( gamma Is adiabatic constant)

The value of |{:(betagamma,betagamma'+beta'gamma,beta'gamma'),(gammaalpha,gammaalpha'+gamma'alpha,gamma'alpha'),(alphabeta,alphabeta'+alpha'beta,alpha'beta'):}| is

Let sin^(-1)alpha+sin^(-1)beta+sin^(-1)gamma=pi and alpha, beta, gamma are non zero real numbers such that (alpha+beta+gamma)(alpha+beta-gamma)=3alphabeta then value of gamma