Evaluate :

`1/sqrt2 + sqrt3 + 1/sqrt2`

Evaluate : 1/( 1 + sqrt (2) ) + 1/( sqrt(2) + sqrt (3) ) + 1/ ( sqrt(3) + sqrt (4) )

1/(1+ sqrt2 + sqrt3)

Evaluate : 1/( sqrt(3) + sqrt(2)) + 1/( sqrt(3 ) - sqrt(2))

Evaluate : 1/( sqrt(3) + sqrt(2)) + 1/( sqrt(3 ) - sqrt(2))

Evaluate : 1/( sqrt(3) + sqrt(2)) + 1/( sqrt(3 ) - sqrt(2))

If sqrt2 = 1.4142 , find the value of 2sqrt2 + sqrt2 + (1)/(2 + sqrt2) + (1)/(sqrt2 - 2)

The value of { 1/(sqrt6 - sqrt5) - 1/(sqrt5 - sqrt4) + 1/(sqrt4 - sqrt3) - 1/(sqrt3 - sqrt2) + 1/(sqrt2 - 1)} is :

The sum of the series 1/(sqrt2 + sqrt1) + 1/(sqrt2 + sqrt3) + ……+ 1/ (sqrt120 + sqrt121) is .

1/(1-sqrt2-sqrt3)=

find the value of 1/(sqrt(2)+sqrt(3))-1/(sqrt(2)-sqrt(3))