The angular momentum of a body is given by ` L =(4t^(2)+2t+7)kgM^(2)s^(-1)`.The net torque acting on the body at `t=2s` is `(a)18NM` `(b)10NM` `(c)16NM` `(d) 8NM`

The angular momentum of a body is given by L=5t^2+2t+1kg m^2/s .The torque acting on the body at t=1 s is

The angular momentum of a particle changes from 4kg m^(2)s^(-1) to 8kg m^(2)s^(-1) is 2 seconds. Calcualte the torque acting on the particle

The angular momentum of a particle changes from 4kg m^(2)s^(-1) to 8kg m^(2)s^(-1) is 2 seconds. Calcualte the torque acting on the particle

The angular displacement of a particle is given by theta=t^(3)+ t^(2)+ t+1 then, its angular velocity at t = 2sec is ……….. rad s^(-1)

The displacement of a body is given by s=(1)/(2)g t^(2) where g is acceleration due to gravity. The velocity of the body at any time t is

A particle is moving on a straight line x + y = 2. Its angular momentum about origin is L = 3t + 2 (kg m^2s^(-1) ). Find the force acting on the particle at t = 2 s. (x and y are in metre)

The position of a body moving along x-axis at time t is given by x= (t^(2)-4t+6)m . The velocity of the body at time t = 3s is

The displace ment of a body at any time t after starting is given by s=10t-(1)/(2)(0.2)t^2 . The velocity of the body is zero after:

The momentum of a body in two perpendicular direction at any time 't' are given by P_(x) =2t^(2) + 6 and P_(y) = (3t^(2))/2 + 3 . The force acting on the body at t= 2 sec is

The angular displacement of a body is given by theta = 2t^(2) + 5t -3 . Find the value of the angular velocity and angular acceleration when t = 2s.