A water drop and a mercury drop is taken inside identical horizontal conical glass Pipes. Then
The water drop tends to move towards the tapered end.
The water drop tends to move towards the wide end.
The mercury drop tends to move towards the tapered end.
The mercury drop tends to move towards the wide end.

Statement-1: Two identical conincal pipes shown in figure have a drop of water. The water drop tens to move towards tapered end. Statement-2: Excess pressure is directed towards centre of curvature and inversely proportional to radius of curvature. Net excess pressure is therefore, directed towards tapered end. So the water drop tends to move towards tapered end.

As water and minerals move toward the vascular cylinder of a root, they must enter the cytoplasm of

As water and minerals move toward the vascular cylinder of a root, they must enter the cytoplasm of

Water on a clean glass surface, tends to spread out, while mercury on the same surface, tends to form drops. Why?

A bomb is dropped from an aeroplane moving horizontally at constant speed. When air resistance is taken into consideration, the bomb

A bomb is dropped from an aeroplane moving horizontal at constant speed. When air resistance is taken into consideration, then the bomb

A man of mass m is standing at one end of a trolley of mass Mand length L placed at rest on a smooth horizontal surface. The man starts moving towards the other end and covers distance L, then distance moved by man w.r.t ground is

A train is moving forward with a horizontal acceleration a. A man sitting in the train drops a coin on the floor of the train . The acceleration of the coin w.r.t man is

A uniform bar of length 12 L and mass 48 m is supported horizontally on two smooth tables as shown in the figure. A small moth (an insect) of mass 8m is sitting on end A of the rod and a spider (an insect) of mass 16 m is sitting on the other end B . Both the insects start moving towards each other along the rod with moth moving at speed 2v and the spider at half of this speed. They meet at a point P on the rod and the spider eats the moth. After this the spider moves with a velocity v//2 relative to the rod towards the end A . The spider takes negligible time in eating the insect. Also, let v = L//T , where T is a constant having value 4 sec .The speed of the bar after the spider eats up the moth and moves towards A is

Immerse a living cell in a hypotonic solution, and water will tend to (a) move into the cell (b) show no net movement (c) move out of the cell (d) move in by endocytosis