Value of `(d^(2)y)/(dx^(2))` at (1,1) for the curve given by `2x^(3)

The solution of (dy)/(dx)=(x^2+y^2+1)/(2x y) satisfying y(1)=1 is given by

The solution of (dy)/(dx)=(x^2+y^2+1)/(2x y) satisfying y(1)=1 is given by

Find (dy)/(dx) for the curve x^(2)=y at the point (1, 1).

Given that y= (3x -1)^(2) + (2x -1)^(3) , find (dy)/( dx) and the points on the curve for which (dy)/(dx)=0

Let y=f (x) and x/y (dy)/(dx) =(3x ^(2)-y)/(2y-x^(2)),f(1)=1 then the possible value of 1/3 f(3) equals :

Given that y=(3x-1)^(2)+(2x-1)^(3) , find (dy)/(dx) and points on the curve for which (dy)/(dx)=0 .

The family of curves represented by (dy)/(dx)=(x^(2)+x+1)/(y^(2)+y+1) and the family represented by (dy)/(dx)+(y^(2)+y+1)/(x^(2)+x+1)=0

The gradient of the curve is given by (dy)/(dx)=2x-(3)/(x^(2)) . The curve passes through (1, 2) find its equation.

A curve satisfies the differential equation (dy)/(dx)=(x+1-xy^2)/(x^2y-y) and passes through (0,0) (1) The equation of the curve is x^2+y^2+2x=x^2y^2 (2) The equation of the curve is x^2+y^2+2x+2y=x^2y^2 (3) x=0 is a tangent to curve (4) y=0 is a tangent to curve

If y = int_(1)^(x) xsqrt(lnt)dt then find the value of (d^(2)y)/(dx^(2)) at x = e