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2/4xx5/6xx2/3xx7/3 =...

`2/4xx5/6xx2/3xx7/3 =`

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Express each of the following in exponential form: (-5)xx(-5)xx(-5) (ii) (-5)/7xx(-5)/7xx(-5)/7xx(-5)/7 (iii) 4/3xx4/3xx4/3xx4/3xx4/3

Simplify: (12^4xx9^3xx4)/(6^3xx8^2xx27) (ii) (25xx5^2xxt^8)/(10^3xxt^4) (iii) (3^5xx10^5xx25)/(5^7xx6^5)

The H.C.F. of 2^4xx3^2xx5^3xx7, 2^3xx3^3xx5^2xx7^2 and 3xx5xx7xx11 is (a) 105 (b) 1155 (c) 2310 (d) 27720

Simplify: 2/3 xx 3/5+5/2 xx 3/5 xx 7/6

If 4xx5xx2=524,3xx7xx2=723 and 6xx8xx7=876 then 9xx4xx5=?

H.C.F.of 3240,3600 and a third number is 36 and their L.C.M.is 2^(4)xx3^(5)xx5^(2)xx7^(2) .The third number is (a) 2^(2)xx3^(5)xx7^(2)(b)2^(2)xx5^(3)xx7^(2)(c)2^(5)xx5^(2)xx7^(2)(b)2^(3)xx3^(5)xx7^(2)

The unit place digit of H.C.F. of 2^(2)xx3^(2)xx5^(3)xx7,2^(3)xx3^(3)xx5^(2)xx7^(2) and 3xx5xx7xx11 is

(3.7xx3.7+2.3xx2.3+2xx3.7xx2.3)/(4.6xx4.6-3.4xx3.4)=

Simplify and express each of the following as power of a rational number: (2/3)^3xx(-6/7)^2xx(-7/4)xx3/2 (iii) -(2/5)^2xx(5/7)^2xx(49)/5+(-4/5)^3xx5/4xx3/4

The L.C.M.of 2^(3)xx3^(2)xx5xx11,backslash backslash2^(4)xx3^(4)xx5^(2)xx7 and 2^(5)xx3^(3)xx5^(3)xx7^(2)xx11 is 2^(3)xx3^(2)xx5 (b) 2^(5)xx3^(4)xx5^(3)(c)2^(3)xx3^(2)xx5xx7xx11(d)2^(5)xx3^(4)xx5^(3)xx7^(2)xx11