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(sqrt3+sqrt5)/(sqrt3-sqrt5)...

`(sqrt3+sqrt5)/(sqrt3-sqrt5)`

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(2sqrt3+sqrt5)(2sqrt3+sqrt5)

3/(sqrt3 - sqrt5)

(2sqrt3 + sqrt5)(2sqrt3 - sqrt5)

Rationalise the denominator of the following (i) 2/(3sqrt3) , (ii) sqrt40/sqrt3 ,(iii) (3+sqrt2)/(4sqrt2) (iv) 16/(sqrt41-5) ,(v) (2+sqrt3)/(2-sqrt3) , (vi) sqrt6/(sqrt2+sqrt3) (vii) (sqrt3+sqrt2)/(sqrt3-sqrt2) ,(viii) (3sqrt5+sqrt3)/(sqrt5-sqrt3) , (ix) (4sqrt3+5sqrt2)/(sqrt48+sqrt18)

(sqrt3-sqrt5)(sqrt5+sqrt3)

Simplify (sqrt3-sqrt5)(sqrt5+sqrt3)

(sqrt5+sqrt3)/(sqrt5-sqrt3)=

Rationalise the denominator of (3sqrt5+sqrt3)/(sqrt5-sqrt3)