`(sqrt3-sqrt2)/(sqrt3+sqrt2)=a-bsqrt6`

3/(sqrt3-sqrt2)=asqrt3-bsqrt2

If x=(sqrt3+sqrt2)/(sqrt3-sqrt2)andy=(sqrt3-sqrt2)/(sqrt3+sqrt2) then find the value of x^(2)+y^(2) ?

(3sqrt2+sqrt3-sqrt6)/(2sqrt3-3sqrt2+sqrt6)=

[(sqrt3 + sqrt2 )/(sqrt3 - sqrt2) - (sqrt3 - sqrt2)/(sqrt3 + sqrt2)] simplifies to

If a=(sqrt3+ sqrt2)/(sqrt3- sqrt2) and b=(sqrt3- sqrt2)/(sqrt3+sqrt2) , then what is the value of a^2+b^2-ab ?

find the values of a and b in each of the following (i) (5+2sqrt3)/(7+4sqrt3) = a-6sqrt3 (ii) (3-sqrt5)/(3+2sqrt5)= asqrt5-(19/11) (iii) (sqrt2+sqrt3)/(3sqrt2-2sqrt3)=2-bsqrt6 (iv) (7+sqrt5)/(7-sqrt5)-(7-sqrt5)/(7+sqrt5)=a+(7/11)bsqrt5

(sqrt2+sqrt7)/(sqrt2-sqrt7)=a+bsqrt(14)