Rationalise:
(a)`4/(sqrt2+sqrt3)`,
(b)`(7+sqrt3)/(2+sqrt3)`
(c)`(2+sqrt3)/(2-sqrt3)`
(d)`(sqrt3+sqrt5)/(sqrt3-sqrt5)`
(e)`(sqrt6+sqrt7)/(sqrt6-sqrt7)`
(f)`(sqrt7-sqrt8)/(sqrt7+sqrt8)`

(sqrt(3)-sqrt(5))(sqrt(3)+sqrt(5))/(sqrt(7)-2sqrt(5))

(sqrt7-sqrt3)^2

(sqrt3 + sqrt7)^2

(sqrt7-sqrt6)/(sqrt7+sqrt6)-(sqrt7+sqrt6)/(sqrt7-sqrt6)=

( sqrt3 + sqrt7)^2

(sqrt(7)+sqrt(3))/(sqrt(7)-sqrt(3))-(sqrt(7)-sqrt(3))/(sqrt(7)+sqrt(3))

rationalise (4)/(2+sqrt(3)+sqrt(7))

7/(sqrt5-sqrt3) =

Rationalise the denominator of the following (i) 2/(3sqrt3) , (ii) sqrt40/sqrt3 ,(iii) (3+sqrt2)/(4sqrt2) (iv) 16/(sqrt41-5) ,(v) (2+sqrt3)/(2-sqrt3) , (vi) sqrt6/(sqrt2+sqrt3) (vii) (sqrt3+sqrt2)/(sqrt3-sqrt2) ,(viii) (3sqrt5+sqrt3)/(sqrt5-sqrt3) , (ix) (4sqrt3+5sqrt2)/(sqrt48+sqrt18)