`int1/(1+sinx+cosx)dx`

int(1)/(1+sinx+cosx)dx=

int(1)/(1+sinx+cosx)dx=

int(1)/(sinx-cosx)dx=

Evaluate: int1/(sinx+cosx)\ dx

Evaluate: int1/(3+2sinx+cosx)dx

int(cosx-sinx)/(1+2sin x cosx)dx is equal to

int(sinx*cosx)dx

Given int_(0)^(pi//2)(dx)/(1+sinx+cosx)=A . Then the value of the definite integral int_(0)^(pi//2)(sinx)/(1+sinx+cosx)dx is equal to

int (dx)/(sinx cosx)=

int(1+sinx)/(sinx(1+cosx))dx