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3. 1/(log2 log2 log3 81)=...

3. `1/(log_2 log_2 log_3 81)=`

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Evaluate log_2 log_2 log_3 81

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log_(2)[log_(2) {log_(2)(log_(3) 81)}] =

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The value of log_4[|log_2{log_2(log_3)81)}] is equal to

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