`int(x+3)/((x-1)(x^2+1))dx`

int(2x+3)/(x(x+1)(x^2+1)dx

int(2x+3)/((x-1)(x^(2)+1))dx=log_(e){(x-1)^((5)/(2))(x^(2)+1)^(a)-(1)/(2)tan^(-1)x+C,x>1 where C is any arbitrary constant,then the value of a'a' is

int(3x)/((x-1)(x-2)(x-3))dx

int(x^(2)+3)/(x-1)dx

int 1/((x-1)(x+2)(2x-3))dx

int(3x+1)/(x^(2)(x+1))dx=

int(x^3(2x-1))/(x-1)dx

int(x^(3))/(2x+1)dx

int(x^(3))/(2x+1)dx

int(x^(3))/(2x+1)dx