`10^(3x)=125` then `10^(-2x)`

((log)_(10)(x-3))/((log)_(10)(x^2-21))=1/2 then find x.

Consider the quantities such that x_(1),x_(2),….x_(10),-1 lex_(1),x_(2)….,x_(10)le 1 and x_(1)^(3)+x_(2)^(3)+…+x_(10)^(3)=0 , then the maximum value of x_(1)+x_(2)+….+x_(10) is

If "log"_(10) x =y, " then log"_(10^(3))x^(2) equals

If 10^(x-1) + 10^(-x-1) = (1)/(3) , then x equals to

If 5^(3x)=\ 125\ and 10^y=0. 001 find x\ a n d\ y

Coefficient of x^(10) in the expansion of (2+3x)e^(-x) is

If log_(10)2,log_(10)(2^(x)-1) and log_(10)(2^(x)+3) are in A.P then the value of x is

If x=(1)/(5)+(1.3)/(5.10)+(1.3.5)/(5.10.15)+….oo then find 3x^(2)+6x.

7/10-x=3/10

Solve the equation 10^((x+1)(3x+4))-2*10^((x+1)(x+2))=10^(1-x-x^(2)).