`int(xsinx)/(1+cos^2x)dx` from `0 to pi`

int_0^pi (xSinx)/(1+Cos^2x)dx

int(1)/(1-cos xsinx)dx=

Evaluate int_(0)^(pi)(xsinx)/((1+cos^(2)x))dx .

int_0^pi (cos^2x)dx ,

int_0^(pi/2) (sinx)/(1+Cos^2x)dx

I_(1) = int_(0)^(pi)(xsinx)/(1+cos^(2)x)dx, I_(2) = int_(0)^(pi)(x^(2)sinx)/((pi^(2)-3pix+3x^(2))(1+cos^(2)x))dx , then

Evaluate (i) int_0^pi (x sin x)/(1+cos^2 x) dx Evaluate (ii) int_0^pi (4x sin x)/(1+ cos^2 x) dx

int_(0)^(pi/2)(1+cos x)dx

int_(0)^(pi//4)(x.sinx)/(cos^(3)x) dx equal to :

int_(0)^( pi)(sin x)/(1+cos^(2)x)dx =