`(1+sqrt5)^4+(1-sqrt5)^4=?`

Find the value/ मान ज्ञात कीजिए: 1/((9-4 sqrt5)^2)+1/((9+4 sqrt5)^2)

Simplify (i) (4+ sqrt(5))/(4-sqrt(5))+(4-sqrt(5))/(4+sqrt(5)) (ii) (1)/(sqrt(3) + sqrt(2)) - (2)/(sqrt(5)-sqrt(3)) -(2)/(sqrt(2) - sqrt(5)) (iii) (2+sqrt(3))/(2-sqrt(3)) + (2-sqrt(3))/(2+sqrt(3)) + (sqrt(3)-1)/(sqrt(3)+1) (iv) (2+sqrt(6))/(sqrt(2)+sqrt(3))+(6sqrt(2))/(sqrt(6)+sqrt(3)) -(8sqrt(3))/(sqrt(6)+sqrt(2))

sqrt(4sqrt(-5)-1)=

(1)/(4sqrt(3)-3sqrt(5))

(1)/(sqrt(9)-sqrt(8))-(1)/(sqrt(8)-sqrt(7))+(1)/(sqrt(7)-sqrt(6))-(1)/(sqrt(6)-sqrt(5))+(1)/(sqrt(5)-sqrt(4))=?

Prove:- ((sqrt5-1)/4)^2 ((sqrt5+1)/4)^2 =(1/16)

The value of (1)/(2)((sqrt(5)+1)/(1+sqrt(5)+sqrt(a))+(sqrt(5)-1)/(1-sqrt(5)+sqrt(a)))(sqrt(a)-(4)/(sqrt(a))+2)sqrt(0.002) is :

Find ( sqrt(5) + 1 )/( sqrt(5 ) - 1) = ( A ) ( 3 + sqrt(5) )/2 ( A ) ( 3 - sqrt(5) )/2 ( A ) ( 3 + sqrt(5) )/4 ( A ) ( 3 - sqrt(5) )/4