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BIHAR BOARD- PREVIOUS YEAR PAPER-प्रश्न पत्र 2022-QUESTION
- int dx/(e^x+e^-x)
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- int(4e^(3x)+1)dx
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- 3int(sqrtx)dx
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- int dx/(sqrt(1-x^2))
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- 2int1/(1+4x^2)dx
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- int((cos^2x+sin^2x)/("cosec"x))dx=
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- 3intdx=
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- d/(dx)(a^(x))=
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- अवकल समीकरण xdy + y dx=0 का हल है
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- int dx/(x^2-1)
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- intdx/(x^2+4)=
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- 2veci.3vecj=
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- 3vecj.2veck-
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- (3veci+4vecj-5veck).veci =
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- (veci+vecj+veck).(2veci+3vecj)=
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- abs(2veci+vecj+2veck)=
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- int0^1 (tan^(-1)x)/(1+x^2) dx=
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- यदि veca=veci+2vecj तथा vecb=2veci+vecj तो |veca+vecb| का मान है
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- सदिश veci+vecj की दिशा में इकाई सदिश है
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- अवकल समीकरण (dy)/(dx)+y=1, y ne1 का हल है
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