The expression for the force is given by `b+(C)/(t^(3))` where `b` and `c` are some physical quantities and `t` is the time.Then the dimensions for `c` are

A force is given by F= at + bt^(2) where , t is the time .The dimensione of a and b are

Write three physical quantities having dimensions [ML^-1 T^-2] .

If the force is given by F=at+bt^(2) with t is time. The dimensions of a and b are

If F=ax+bt^(2)+c where F is force, x is distance and t is time. Then what is dimension of (axc)/(bt^(2)) ?

A force F is given by F = at+ bt^(2) , where t is time. The dimensions of a and b are

When a wave transverses in a medium, the displacement of a particle located at distance x at time t is given by y=a sin (bt-cx) where a, b and c are constants of the wave. The dimension of b//c are same as that of:

Force acting on a particle is given by F=(A-x)/(Bt) , where x is in metre and t is in seconds. The dimensions of B is -