If mean of `x,2x+1,2x-1` is 10, then value of x is
2
4
6
3

If sum_(i=1)^5x_i^2=40&sum_(j=6)^(10)x_j^2=20 and mean of x_1,x_2, ...,x_5 is 1 and mean of x_6,x_7, ...,x_(10) is 2 then variance of x_1,x_2 ,...x_(10) is

The mean of 2,7,6 and x is 5 and the mean of 18,1,6,x and y is 10 What is the value of y

If x^(4) - 3x^(2) - 1 = 0 , then the value of (x^(6)-3x^(2)+(3)/(x^(2))-(1)/(x^(6))+1) is :

If x^2 + 1/x^2 = 6 , find the value of x^4 + 1/x^4

Let f(x_1,x_2,x_3,x_4)=x_1^2+x_2^2+x_3^2+x_4^2-2(x_1+x_2+x_3+x_4)+10 and x_1,x_3 in [-1,2] and x_2,x_4 in [1,4] then the maximum value of f is

If x^2 - 3x + 1 = 0 , then the value of (x^6 + x^4 + x^2 + 1)/(x^3) will be