The capacity of a parallel plate air condenser is `m mu F`.If a dielectric of dielectric constant `8` is introduced between the plates,then its new capacity is `24 mu F`. Find the value of `m`.

The capacity of a parallel plate condenser is 10 muF without dielectric. Dielectric of constant 2 is used to fill half the distance between the plates, the new capacitance in muF is

A parallel plate capacitor has a capacity c. If a medium of dielectric constant K is introduced between plates, the capacity of capacitor becomes

A parallel plate condenser is immersed in an oil of dielectric constant 2 . The field between the plates is

The capacitance of a parallel plate capacitor is 10muF . When a dielectric plate is introduced in between the plates, its potential becomes 1/4th of its original value. What is the value of the dielectric constant of the plate introduced?

The distance between the plates of a parallel plate condenser is 8 mm and P.D. 120 volts. If a 6 mm thick slab of dielectric constant 6 is introduced between its plates, then

The capacity of a parallel plate condenser filled with material of dielelctric constant 8 is 16 muF . Its capacity, if the dielectric is removed , will be

The capacity of a parallel plate capacitor with air is 18 pF. When a dielectric material is inserted in the space between the plates, its capacity becomes 108 pF. Calculate the permittivity of the material. What is the material?

The capacity of a parallel plate condenser with dielectric constant 10 is 16xx10^(-6)F . If the dielectric is removed, then the new capacity will be

A parallel plate condenser is made up of two plates, each of surface area 40cm^(2) , separated by a distance of 0.4 cm. If a material of dielectric constant 10 is introduced between the plates, then the capacity of the condenser is