If in a triangle ABC,AB=5 units ∠B=cos^-1(3/5) and radius of circumcircle of ∆ABC is 5 units, then the area of triangle ABC is

In a triangle ABC, cos A+cos B+cos C=

A circumcircle is a circle which passes through all vertices of a triangle and an incircle is a circle which is inscribed in a triangle touching all sides of a triangle. Let ABC be a right angled triangle whose radius of circumcircle is 5 and its one side AB = 6. The radius of incircle of triangle ABC is r. The value of r is

A circumcircle is a circle which passes through all vertices of a triangle and an incircle is a circle which is inscribed in a triangle touching all sides of a triangle. Let ABC be a right-angled triangle whose radius of the circumcircle is 5 and its one side AB = 6. The radius of incircle of triangle ABC is r. Area of Delta ABC is

In Fig. 3, the area of triangle ABC (in sq. units) is :

In a triangle ABC, medians AD and CE are drawn. If AD=5, angle DAC=pi/8 and angle ACE=pi/4 then the area of the triangle ABC is equal to (5a)/b, then a+b is equal to

Let A=(1,2), B=(3,4) and C=(x,y) lie on the circumcircle of triangle ABC having AB as a diameter such that area of triangle ABC=1 the maximum number of position of C in the x-y plane is:

Triangle ABC is inscribed in a circle, such that AC is a diameter of the circle and angle BAC is 45^@ . If the area of triangle ABC is 72 square units, how larger is the area of the circle than the area of triangle ABC ?

A triangle ABC right angled at A has points A and B as (2, 3) and (0, -1) respectively. If BC = 5 units, then the point C is

In the given figure , ABC is a triangle in which angle BAC = 30 ^(@) . Show that BC is equal to the radius of the circumcircle of the traiangle ABC , whose centre is O.

In a triangle ABC,vertex angles A,B,C and side BC are given .The area of triangle ABC is