Home
Class 12
MATHS
Equation of line in 3D...

Equation of line in 3D

Promotional Banner

Similar Questions

Explore conceptually related problems

The Cartesian equation of a line is (x-3)/(2)=(y+1)/(-2)=(z-3)/(5). Find the vector equation of the line.

The cartesian equation of a line is (x-3)/(2)=(y+1)/(-2)=(z-3)/(5). Find the vector equation of the line.

The Cartesian equation of a line is (x-5)/3=(y+4)/7=(z-6)/2. find the vector equation of the line.

The Cartesian equation of a line is (x+3)/(2)=(y-5)/(4)=(z+6)/(2). Find the vector equation for the line.

The cartesian equation of a line is 3x - 1 = 6y + 2 = 1 - z . Find the vector equation of the line .

The cartesian equation of a line is 3x + 1 = 6 y - 2 = 1 -z . Find the vector equation of the line.

Equation of line passing through the point (2,-3) and perpendicular to the straight line joining the points (5,7) and (-6,3).

The cartesian equations of line is : (x - 1)/(2) = (y - 2)/(3) = (z -3)/(4) . Write the vector equation.

The cartesian equation of a line is (x+2)/(1) = (y+3)/(-2) = (z)/(3) , find its vector equation.

Equation of a line which passes through A(2,3) and makes an angle 45^@ with x-axis. If this line meets the line x+y+1=0 at the points P, then distance AP is (A) 2sqrt3 (B) 3 sqrt 2 (C) 5sqrt 2 (D) 2sqrt5