A capacitor of some capacitance is charged by a `12V` battery.Now the space between the plates of capacitors is filled with a dielectric of dielectric constant `K=0.5` and again it is charged. The magnitude of the charge will

A parallel plate capacitor of capacitance 10 muF is connected across a battery of emf 5 mV. Now, the space between the plates of the capacitors is filled with a deielectric material of dielectric constant K=5. Then, the charge that will flow through the battery till equilibrium is reached is

Two parallel plate capacitors, each of capacitance 40 muF, are connected is series. The space between the plates of one capacitor is filled with a dielectric material of dielectric constant K =4. Find the equivalent capacitacne of the system.

Consider a disconnected. Plate capacitor of capacity 10 mu with air filled in the gap between the plates. Now one-half of the space between the plates is filled with a dielectric of dielectric constant 4 as shown in .The capacity of the capacitor changes to .

Consider a parallel plate capacitor of 10 muF (micro-farad) with air filled in the gap between the plates. Now one half of the space between the plates is filled with a dielectric of dielectric constant 4 , as shown in the figure. The capacity of the capacitor charges to

Two parallel plate air filled capacitors each of capacitance C, are joined in series to a battery of emf V. The space between the plates of one of the capacitors is then completely filled up with a uniform dielectric having dielectric constant K. The quantity of charge which flows through the battery is -

Two identical parallel plate capacitors of capacitance C each are connected in series with a battery of emf, E as shown. If one of the capacitors is now filled with a dielectric of dielectric constant k, the amount of charge which will flow through the battery is (neglect internal resistance of the battery)

A capacitor with air as the delectric is charged to a potential of 100 volts. If the space between the plates is now filled with a dielectric of dielectric constant 10 , the potential difference between the plates will be

An air capacitor of capacity C = 10 mu F is connected to a constant voltage battery of 12 V . Now the space between the plates is filled with a liquid of dielectirc constant 5 . The charge that flows now from battery to the capacitor is

A parallel plate capacitar, of capacitance, 20 mu F , is connected to a 100 V supply. After some time, the battery is disconnected , and the space, between the plates of the capacitor is filled with a dielectric, of dielectric constant 5. Calculate the energy stored in the capacitar (i) before (ii)after dielectric has been put in between its plates.