The vector form of Coulomb's law is (A) `vec F=(1)/(4 pi epsilon_(0))*(q_(1)q_(2))/(|vec r|^(3))vec r` (B) `vec F=(1)/(4 pi epsilon_(0))*(q_(1)q_(2))/(|vec r|^(3))` (C) `vec F=(1)/(4 pi epsilon_(0))*(q_(1)q_(2))/(r^(2))vec r` (D) `vec F=(1)/(4 pi epsilon_(0))*(q_(1)q_(2))/(r)vec r`

The vector form of Coulomb's law is (A) vec F=(1)/(4 pi epsilon_(0))*(q_(1)q_(2))/(|vec r|^(3))vec r (B) vec F=(1)/(4 pi epsilon_(0))*(q_(1)q_(2))/(r^(3)) (C) vec F=(1)/(4 pi epsilon_(0))*(q_(1)q_(2))/(r^(2))vec r (D) vec F=(1)/(4 pi epsilon_(0))*(q_(1)q_(2))/(r)vec r

[" Two uniformly charged non "],[" conducting spheres of radii "R_(1)" and "],[R_(2)" having charges "Q_(1)" and "Q_(2)],[" respectively are seperated by "],[" distance "r" .Total electrostatic "],[" energy of this system is "],[qquad [U=(1)/(4 pi epsilon_(0)){(3Q_(1)^(2))/(5R_(1))+(3Q_(2)^(2))/(5R_(2))+(Q_(1)Q_(2))/(r)}],[U=(1)/(4 pi epsilon_(0)){(3Q_(1)^(2))/(5R_(1))+(3Q_(2)^(2))/(5R_(2))-(Q_(1)Q_(2))/(r)}],[U=(1)/(4 pi epsilon_(0)){(Q_(1)^(2))/(5R_(1))+(3Q_(2)^(2))/(5R_(2))-(Q_(1)Q_(2))/(r)}],[U=(1)/(4 pi epsilon_(0)){(3Q_(1)^(2))/(5R_(1))+(3Q_(2)^(2))/(R_(2))+(Q_(1)Q_(2))/(r)}]]

41.Self energy of conducting sphere of radius r carrying charge is (1) (Q^(2))/(8 pi epsilon_(0)(r) (2) (Q^(2))/(4 pi epsilon_(0)(r) (3) (Q^(2))/(6 pi epsilon_(0)(r) (4) (Q^(2))/(2 pi epsilon_(0)(r)

The Bohr model for the H-atom relies on the Coulomb's law of electrostatics . Coulomb's law has not directly been varified for very short distances of the order of angstroms. Suppos-ing Coulomb's law between two oppsite charge +q_(1),-q_(2) is modified to |vec(F)|=(q_(1)q_(2))/((4piepsilon_(0))r^(2))1/r^(2),rgeR_(0) =(q_(1)q_(2))/((4piepsilon_(0))r^(2))1/R_(0)^(2)(R_(0)/r)^(epsilon), rleR_(0) Calculate in such a case , the ground state enenergy of H-atom , if epsilon 0.1,R_(0)=1Å

There are three charges Q_(1) columb Q_(2) columb and Q_(3) columb. Q_(2) and Q_(3) are fixed at positive (0 0) and (30 0) respectively.Now Q_(1) moves in circular path in x -y plane of radius 40 cm with help of external agent starting from (0 40) about origin then work done by external agent is till Q_(1) crosses x axis (40 0) given co-ordinates are in centimeters: 1) (Q_(1)Q_(3))/(4 pi epsilon_(0)) joule 2) (Q_(1)Q_(3))/(2 pi epsilon_(0)) joule 3) (2Q_(1)Q_(3))/(pi epsilon_(0)) joule 4) (2Q_(1)(Q_(2)+Q_(3)))/(pi epsilon_(0)) joule

There are three charges Q_(1) columb Q_(2) columb and Q_(3) columb. Q_(2) and Q_(3) are fixed at positive (0,0) and (30,0) respectively.Now Q_(1) moves in circular path in x -y plane of radius 40 m with help of external agent starting from (0 ,40) about origin then work done by external agent is till Q_(1) crosses x axis (40, 0) given co-ordinates are in centimeters: (1) (Q_(1)Q_(3))/(4 pi epsilon_(0)) joule (2) (Q_(1)Q_(3))/(2 pi epsilon_(0)) joule (3) (2Q_(1)Q_(3))/(pi epsilon_(0)) joule (4) (2Q_(1)(Q_(2)+Q_(3)))/(pi epsilon_(0)) joule

if vec(P) xx vec(R ) = vec(Q) xx vec(R ) , then

If vec r=3vec p+4vec q and 2vec r=vec p-3vec q then

The electric field at point P due to a charged ball is given by E_(p)=(1)/( 4pi epsilon_(0))(q)/(r^(2)) To measure 'E' at point P, A test charge q_(0) is placed at point P and measure electric force F upon the test charge. Check whether (F)/(q_(0)) is equal to (1)/(4pi epsilon_(0))(q)/(r^(2)) or not .