`(3x+1)/(6)+(2x-3)/(7)=(x+3)/(8)+(3x-1)/(14)`

Solve the following equations and also check your result in each case: (i) ((3x+1))/(16)+((2x-3))/7=((x+3))/8+((3x-1))/(14) (ii) ((1-2x))/7-((2-3x))/8=3/2+x/4 (iii) (9x+7)/2-\ (x-(x-2)/7)=36 (iv) 0. 18\ (5x-4)=\ 0. 5 x+0. 8

(4x+1)/(3)+(2x-1)/(2)=6+(3x-7)/(5)

Solve : (3x +4)/(7) - (x +5)/(14) = (x)/(28) + (x +1)/(14) The following steps are involved in solving the above problem. Arrange them in sequential order (A) 5x + 3 = (3x + 2)/(2) rArr 10 x + 6 = 3x + 2 (B) rArr 7x = -4 (C) Given (3x + 4)/(7) - (x + 5)/(14) = (x)/(28) + (x +1)/(14) rArr (6x + 8 -x -5)/(14) = (x + 2x + 2)/(28) (D) rArr x = -(4)/(7)

Solve : (7x +3)/(4) + (9x -5)/(8) = (16x-3)/(16) The following steps are involved in solving the above problem. Arrange them in sequential order (A) x = (-5)/(30) = (-1)/(6) (B) (7x + 3)/(4) + (9x -5)/(8) = (16x-3)/(16) rArr (14x + 6 + 9x -5)/(8) = (16x -3)/(16) (C) (23x + 1)/(8) = (16x -3)/(16) rArr 23x + 1 = (16x -3)/(2) (D) 46x + 2 = 16x - 3 rArr 30 x = -5

" If (3x^(3)-8x^(2)+10)/((x-1)^(4))=(3)/(x-1)+(1)/((x-1)^(2))-(7)/((x-1)^(3))+(k)/((x-1)^(2)) then "k=

Add: (3x^(2) - (1)/(5)x + (7)/(3)) + ((-1)/(4)x^(2) + (1)/(3)x - (1)/(6)) + (-2x^(2) - (1)/(2)x + 5)

((1-2x) / (7))-((2-3x) / (8)) = (3) / (2) + (x) / (4)

(2x-1)/(3)+(3x+2)/(2)+7=(1)/(6)+(4x+3)/(6)