The angular momentum of a body is given by `L=``(4t^(2)+2t+7)kgm^(2)s^(-1)`.The net torque acting on the body at `t=2s` is

The angular momentum of a body is given by L=5t^2+2t+1kg m^2/s .The torque acting on the body at t=1 s is

If there a change in the angular momentum of a body from "5 kg-m"^(2)//s to "8 kg-m"^(2)//s in 4 seconds, then the torque acting on the body is

The angular momentum of a rotating body changes from A_(0) to 4 A_(0) in 4 min. The torque acting on the body is

Momentum of a body moving in a straight line is p = (2t^3 + t^2 + 2t + 1) kg m/s. Force acting on a body at t = 2 sec.

Total angular momentum of a rotating body remains constant, if the net torque acting on the body is

The momenta of a body in two perpendicular directions at any time 't' are given by P_(x)=2t^(2) +6 and P_(y)=(3t^(2))/(2)+3 . The force acting on the body at t =2 sec is .

The angular displacement at any time t is given by theta(t) = 2t^(3)-6^(2) . The torque on the wheel will be zero at

Under a constant torque, the angular momentum of a body changes from 2x to 5x in 8 sec. The torque acting on the body is