Find the value of `|vecx|` if for a unit vector a`(vecx-veca)(vecx+veca)=8`

Find |vecx|, if for a unit vector veca, (vecx-veca).(vecx+veca) = 12 .

If veca is unit vector and (vecx-a).(vecx+a)=12 then find |x| .

If is given that vecx= (vecbxxvecc)/([veca,vecb,vecc]), vecy=(veccxxveca)/[(veca,vecb,vecc)], vecz=(vecaxxvecb)/[(veca,vecb,vecc)] where veca,vecb,vecc are non coplanar vectors. Find the value of vecx.(veca+vecb)+vecy.(vecc+vecb)+vecz(vecc+veca)

It is given that : vec x = (vec b xx vec c)/([veca vec b vec c]) ; vecy=(vec c vec a)/([veca vecb vecc]) ; vecz=(veca xx vecb)/([veca vecb vecc]) where a, b, c are non-coplanar vectors; show that x, y, z also form a non-coplanar system. Find the value of vecx*(veca+vecb)+vecy*(vecb+vecc)+vecz(vecc+veca) .

The unit vector parallel to vecA is

Find the angle between unit vector veca and vecb so that sqrt(3) veca - vecb is also a unit vector.

Consider three vectors veca, vecb and vecc . Vectors veca and vecb are unit vectors having an angle theta between them For vector veca,|veca|^2=veca.veca If veca_|_vecb and veca_|_vecc then veca||vecbxxvecc If veca||vecb, then veca=tvecb Now answer the following question: If vecc is as unit vector such that veca.vecb=veca.vecc=0 and theta= (pi/6) then veca= (A) +-1/2(vecbxxvecc) (B) +-(vecbxxvecc) (C) +-2(vecbxxvecc) (D) none of these

Let veca , vecb and vecc be unit vectors such that veca+vecb+vecc=vecx, veca.vecx =1, vecb.vecx = 3/2 ,|vecx|=2 then find theh angle between vecc and vecx .

Let veca , vecb and vecc be unit vectors such that veca+vecb+vecc=vecx, veca.vecx =1, vecb.vecx = 3/2 ,|vecx|=2 then find theh angle between vecc and vecx .

If vecx and vecy are two vector such that abs(vecx)=abs(vecy) and abs(vecx-vecy)=nabs(vecx+vecy) then angle between vecx and vecy