`(-4)^(-2)times(5)^(-3)times(5)^(-4)`

solve it : (ii) (-3)/(5)times(-3)/(5)times(-3)/(5)times(-3)/(5) (iii) (-9)/(2)times(4)/(2)times(-4)/(2)times(-4)/(2)times(-4)/(2)times(-4)/(2) (iv) (-5)/(3)times(-5)/(3)times(-5)/(3)times(-5)/(3) (v) (-6)/(2)times(-6)/(2)times(-6)/(2)times(-6)/(2)times(-6)/(2)

"(a^(-3)times b^(-2)times c^(-5)times d^(5))/(a^(4)times b times c^(-3)times d^(4))

Simplify (3^(-5)times5^(-7)times(-2)^(3))/(3^(4)times5^(-2)times(-2)^(-3))

(5^(-3)times a^(3)times c^(4))/(5^(2)times a^(-4)times c^(3))

Evaluate : (( 2^-3)^2 times ( 3^2)^-3 times ( 5^-4 )^2 ) / ((2^-2)^5 times ( 3^2 )^-2 times ( 5^-3 )^4)

3^(-5)times10^(-4)times(5^(4))/(5^(2))times6^(-5)=

(5^(4)times x^(8)times y^(5))/(4^(5)times x^(5)y^(2))

5.Simplify : (i) (3/4)times(2/5)+(3/4)times(3/5)

Proved that (2)/(3)times[(-6)/(7)times(4)/(5)]=[(2)/(3)times(4)/(5)]times((-6)/(7))

Simplify and write the answer in the exponential form.(i) (2^(5)-:2^(8))^(5)xx2^(-5) (ii) (-4)^(-3)xx(5)^(-3)xx(-5)^(-3)( iii) (1)/(8)xx(3)^(-3) (iv) (-3)64xx((5)/(3))^(4)