Geometrical Isomerism (G.I.) Due To Ring|GI Due To Double Bond Inside The Ring|Cumulenes|Questions|G.I. In C=N System|Calculation Of No. GI|Questions|GI In Spiro Compounds|OMR

Geometrical isomerism in Double bonded system | Spiro Compounds

Calculation OF G.I || Introduction OF contributional Isomerism

G.I. properties

Nomenclature Systems Of Geometrical Isomers|Priority Rules (CIP Sequence Rule)|Examples|Optical Isomerism|Plane Polarised Light|Chiral Centre|Questions|Asymmetric Molecule|Plane Of Symmetry|Centre Of Symmetry|Questions|Projection Formula|Fischer Projection|Relative Configuration (D/L)|Threo & Erythro System|Enantiomers|Diastereomers|Meso Compound|Racemic Mixture|Conformational Isomerism|Representation Of 3-D Molecules|Stability Factor Of Conformers|Conformers Of Ethane|Potential Energy Graph|OMR

We Learnt From Galileo's Experiment That|Examples|Calculation Of The Acceleration Due To Gravity (g)|Exercise Questions|Important Points|Summary

Read the passage given below and answer the following questions : The existence of coordination compounds with the same formula but different arragements of the ligands was crucial in the development of coordination chemistry. Two or more compounds with the same formula but different arrangements of the atoms are called isomers. Isomers are compounds with the same molecular formula but different structural formulas and do not necessarily share similar properties. There are many different classes of isomers, like stereoisomers, enantiomers, and geometrical isomers. There are two main forms of isomerism: structural isomerism and stereoisomerism. The different chemical formulas in structural isomers are caused either by a difference in what ligands are bonded to the central atoms or how the individual ligands are bonded to the central atoms. The following questions are multiple choice questions. Choose the most appropriate answer: Due to the presence of ambidentate ligands coordination compounds show isomerism. Palladium complexes of the type [Pd(C_(6)H_(5))_(2)(SCN)_(2)] and [Pd(C_(6)H_(5))_(2)(NCS)_(2)] are

Write the structure formulas for the following: (i) cis-Oct- 3 -ene (ii) 2,4 -Dimethylpent- 2 -ene (iii) 3,4 -Dimethylcyclopentene (iv) 1,3 -Dimethylcyclohexene (v) Vinylcyclopentane Strategy: first write down the parent C chain. Then introduce the double bond between the suitable C atoms. Finally attach the substituents and the suitable number of H atoms to satisfy the valency of C's . In cycloalkenes, one can write down the double bonds anywhere in the ring but the position of substituents is fixed by the position of double bonds.